SOLUTION: Events A and B have probablities P(A)=0.4, P(B)=0.65, and P(A union B)=0.85
a) Calculate P(A intersect B) I said 0.26 and was wrong.
b) State with a reason whether events A
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-> SOLUTION: Events A and B have probablities P(A)=0.4, P(B)=0.65, and P(A union B)=0.85
a) Calculate P(A intersect B) I said 0.26 and was wrong.
b) State with a reason whether events A
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Question 919844: Events A and B have probablities P(A)=0.4, P(B)=0.65, and P(A union B)=0.85
a) Calculate P(A intersect B) I said 0.26 and was wrong.
b) State with a reason whether events A and B are independent.
c) State with a reason whether events A and B are mutually exclusive. Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!
Re TY: Yes! on the .20. Good Work.
a) P(A or B) = P(A) + P(B) - P(A and B)
P(A and B)= P(A) + P(B)- P(A or B) = .4 + .65 - .85 =
......
b) State with a reason whether events A and B are independent.
Have Unique Individual Probabilities Independent of one another
.........
c) events A and B are NOT mutually exclusive:P(A and B) = .85
