SOLUTION: Terence’s dog has a dog house that is 3’ wide and 5’ long. He is building a fence so that way the dog can stay within 4’ of the doghouse on each side. What
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-> SOLUTION: Terence’s dog has a dog house that is 3’ wide and 5’ long. He is building a fence so that way the dog can stay within 4’ of the doghouse on each side. What
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Question 91982: Terence’s dog has a dog house that is 3’ wide and 5’ long. He is building a fence so that way the dog can stay within 4’ of the doghouse on each side. What would be the area inside the fence? Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! adding 4' to BOTH ends of a 3' width and 5' length gives an area that is 11' by 13' ... or a=11(13) ... a=143sq'
