Question 919792: 46% of all pets sold at a pet store are dogs. One day, 8 people arrive at the store and purchase pets.
(Note: One pet is purchased per person.)
(a) What is the probability that exactly 4 of them are dogs?
(b) If the store has only 6 dogs, what is the probability that they have sufficient dogs for sale that day?
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! p(dog) = .46, n = 8
P(x = 4) = binompdf(8, .46, 4)
P(x = 6) = binompdf(8, .46, 6)
Recommend Using stattrek.com to check Your TI Calculator Results
until You are comfortable using it.
Or
P(x = 4) = 8C4(.46^4)(.54)^4
P(x = 6) = 8C6(.46^6)(.54)^2
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