Question 919647: Solve the equation. (Enter your answers as a comma-separated list. Use n as an integer constant. Enter your response in radians.)
(2 sin2 x − 1)(tan2 x − 3) = 0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Solve the equation. (Enter your answers as a comma-separated list. Use n as an integer constant. Enter your response in radians.)
(2 sin2 x − 1)(tan2 x − 3) = 0
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I assume sin2 and tan2 are meant to be sin^2 and tan^2. Please use the "^" next time if this is the case.
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For interval:(0,2π)
(2sin2^x−1)(tan^2x−3)=0
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2sin2^x−1=0
sin^2x=1/2
sinx=±√(1/2)=±1/√2=±√2/2
x=π/4, 3π/4, 5π/4, 7π/4
or
tan^2x−3=0
tanx=±√3
x=π/3, 2π/3, 4π/3, 5π/3
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