SOLUTION: if 7 times the square of a number is added to the number itself, the result is 66

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Question 919620: if 7 times the square of a number is added to the number itself, the result is 66
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
7n^2 + n = 66
7n^2 + n - 66 = 0
x+=+%28-1+%2B-+sqrt%28+1849+%29%29%2F%2814%29+
x+=+%28-1+%2B-+43%29%2F%2814%29+
x = 3
0r
x = -44/14 = -3 1/7