Question 919587: A recent national survey found that high school students watched an average (mean) of 6.4 DVDs per month with a population standard deviation of .60. A random sample of 43 college students revealed that the mean number of DVDs watched last month was 5.70. At the .05 significance level, can we conclude that college students watch fewer DVDs a month than high school students?
(a)Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)
(b)What is the p-value?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A recent national survey found that high school students watched an average (mean) of 6.4 DVDs per month with a population standard deviation of .60. A random sample of 43 college students revealed that the mean number of DVDs watched last month was 5.70. At the .05 significance level, can we conclude that college students watch fewer DVDs a month than high school students?
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(a)Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)
sample mean = 5.7
test stat::: z(5.7) = (5.7-6.4)/0.6 = -1.6667
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(b)What is the p-value?
Since Ha is u < 6.4, your's is a right-tail test
p-value = p(z < -1.6667) = normalcdf(-100,-1.6667) = 0.0478
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Cheers,
Stan H.
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