SOLUTION: Solve on interval [0 , 2pi)
2 sin ^ 2 + sin x = 1
someone please help show me the steps and how to arrive at the correct solution. I really need an example to work from
th
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-> SOLUTION: Solve on interval [0 , 2pi)
2 sin ^ 2 + sin x = 1
someone please help show me the steps and how to arrive at the correct solution. I really need an example to work from
th
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Question 919524: Solve on interval [0 , 2pi)
2 sin ^ 2 + sin x = 1
someone please help show me the steps and how to arrive at the correct solution. I really need an example to work from
thank you Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Solve on interval [0 , 2pi)
2 sin ^ 2 + sin x = 1
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Do you 2sin^2(x) ?
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Don't put spaces like that.
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2sin^2(x) + sin(x) = 1
2sin^2(x) + sin(x) - 1 = 0
(2sin(x) - 1)*(sin(x) + 1) = 0
sin(x) = -1
x = pi
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sin(x) = 1/2
x = pi/6, 5pi/6
