Question 919439: I really need your help in solving this problem. I appreciate your time and efforts. Have a terrific day :) Here is the question?
Gravity. The force with which the Earth attract an object above the Earth's surface varies inversely as the square of the distance of the object from the center of the Earth. An object 4,000 miles from the center of the Earth is attracted with a force of 80 pounds. Find the force of attraction if the object were 5,000 miles from the center of the Earth?
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! force of gravity between two objects is given by
F = (m1 * m2)G / d^2, where m1, m2 are the masses of the two objects, d is the distance between them, and G is force of gravity 32.2 feet per second ^2
we are given in the example
80 = (m1 * m2)G / 4000^2
(m1 * m2)G = 80 * 4000^2 = 1280000000
therefore
F = 1280000000 / 5000^2 = 51.2 pounds
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