SOLUTION: p/q=1/3(sqrt[h+2k/3h+k] make h the subject of the formulae

Algebra ->  Square-cubic-other-roots -> SOLUTION: p/q=1/3(sqrt[h+2k/3h+k] make h the subject of the formulae      Log On


   

Question 919326: p/q=1/3(sqrt[h+2k/3h+k]
make h the subject of the formulae
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

p%2Fq=%281%2F3%29%28sqrt%28%28h%2B2k%29%2F%283h%2Bk%29%29%29
make h the subject
%28p%2Fq%29%2F%281%2F3%29=sqrt%28%28h%2B2k%29%2F%283h%2Bk%29%29
3p%2Fq=sqrt%28%28h%2B2k%29%2F%283h%2Bk%29%29 ......raise both sides to the power of two

%283p%2Fq%29%5E2=%28sqrt%28%28h%2B2k%29%2F%283h%2Bk%29%29%29%5E2

9p%5E2%2Fq%5E2=%28h%2B2k%29%2F%283h%2Bk%29 ........cross multiply

9p%5E2%283h%2Bk%29=%28h%2B2k%29q%5E2

27p%5E2%2Ah%2B9p%5E2%2Ak=h%2Aq%5E2%2B2k%2Aq%5E2


27p%5E2%2Ah-h%2Aq%5E2=2k%2Aq%5E2-9p%5E2%2Ak

%2827p%5E2-q%5E2%29h=2k%2Aq%5E2-9p%5E2%2Ak

h=%282k%2Aq%5E2-9kp%5E2%29%2F%2827p%5E2-q%5E2%29