SOLUTION: Two sides an angle of a triangle are given, determine whether the given measurements produce one triangle, two triangles or no triangle at all. a = 10 b = 9 A = 30 degrees

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Question 919179: Two sides an angle of a triangle are given, determine whether the given measurements produce one triangle, two triangles or no triangle at all.
a = 10 b = 9 A = 30 degrees

(Im very stuck on this problem and the choices they give us is like B = what or C = and also C1 and B1 etc.
please help!
thank you

Found 3 solutions by DrBeeee, MathTherapy, KMST:
Answer by DrBeeee(684) About Me  (Show Source):
You can put this solution on YOUR website!
I don't know how to draw on line, so bear with me!
Draw a horizontal line 10 units long and label it AC, this is your line a.
Use your protractor to draw a line 30 degrees above and about point A. This is angle A = 30. Now measure 9 units along that 30 degree line and label the end point as B. This line AB is your line b = 9. Now draw a line to join point B and point C on line AC. This line is c. Got the triangle? Hope so.
Now you need to do some trig to find B, C and c.
To do this, drop a line from point B down to and perpendicular to line AC. Label the point of intersection M, and label the line as h. Now you have a right triangle ABM, where AB = 9 and A = 30 degrees. Label the line AM as x. then we have
(1) cos(A) = x/9 or
(2) x = 9*cos(A) or
(3) x = 9*cos(30) or
In the same triangle we have
(4) sin(A) = h/9 or
(5) h = 9*sin(30) or
(6) h = 4.5 (this is exact because sin(30) = 1/2)
So far so good.
Look at your triangle and label the line MC as y. Note that
(7) x + y = a = 10 or
(8) y = 10 - x or
(9) y = 10 - 9*cos(30)
Also note that
(10) tan(C) = h/y or
(11) tan(C) = 4.5/(10 - 9*cos(30)) or
(12) C = arctan(4.5/(10 - 9*cos(30)))
Use your calculator to find
(13) angle C is approx 63.887... degrees.
Using the identity
(14) A+B+C = 180 we have
(15) 30 + B + 63.887... = 180 or
(16) angle B is approx 86.113... degrees.
Lastly we need c. We can use
(17) sin(C) = h/c or
(18) c = 4.5/sin(C)
Using your calculator and C of (12) we get
(19) line c is approx 5.0115
We can check c using
(20) c^2 = y^2 + h^2 or
Is (5.0115^2 = 2.20577^2 + 4.5^2)?
Is (5.0115^2 = 4.8654... + 20.25)?
Is (5.0115^2 = 25.1154...)?
Is (5.0115^2 = 5.0115^2)? Yes
Answer: The given values form a single scalene triangle ABC, whose sides are a=10, b=9 and c=5.0115... with anles A = 30, B = 86.113... and C = 63.887... degrees.















Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
Two sides an angle of a triangle are given, determine whether the given measurements produce one triangle, two triangles or no triangle at all.
a = 10 b = 9 A = 30 degrees

Use the law of sines to determine how many possible triangles there are
%28sin+A%29%2Fa+=+%28sin+B%29%2Fb
sin+30%2F10+=+sin+B%2F9
10 sin B = 9 sin 30 -------- Cross-multiplying
sin+B+=+%289+sin+30%29%2F10
sin+B+=+26.7427%5Eo
Therefore, angles are: A: 30%5Eo, B: 27%5Eo, and C: 123%5Eo (180 – 30 - 27, or 180 - 57)
Now, since sin ∠B is: 27%5Eo, another possible measure of ∠B is its reference angle: 153%5Eo, in the 2nd quadrant.
However, ∠B CANNOT possibly be 153%5Eo since that would result in ∠B (153%5Eo) + ∠A (30%5Eo) being equal to 183%5Eo,
which is > 180%5Eo.
Thus, ONLY ONE (1) triangle can be formed with the given measurements

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Having the measures of one angle and the opposite side, you can use law of sines to try to solve the triangle.
In this case, you can use A, a and b to find B, C and c).
Law of sines says that sin%28A%29%2Fa=sin%28B%29%2Fb , so
sin%2830%5Eo%29%2F10=sin%28B%29%2F9-->0.5%2F10=sin%28B%29%2F9-->9%2A0.5%2F10=sin%28B%29-->sin%28B%29=0.45
That means that highlight%28B=26.74%5Eo%29 (rounded).
That is the only possible measure for B for the only possible triangle with the given measurements.
sin%28180%5Eo-26.74%5Eo%29=sin%28153.26%5Eo%29=0.45 too,
but you could not have angles measuring 30%5Eo and 153.26%5Eo in the same triangle,
because 30%5Eo%2B153.26%5Eo=183.26%5Eo%3E180%5Eo.
So there is only one option, one triangle,
just one B and one C , no B1 or C1 .
C=180%5Eo-%28A%2BB%29-->C=180%5Eo-%2830%5Eo%2B26.74%5Eo%29-->C=180%5Eo-56.74%5Eo-->highlight%28C=123.26%5Eo%29 (rounded).
Law of sines also says sin%28A%29%2Fa=sin%28C%29%2Fc<-->a%2Fsin%28A%29=c%2Fsin%28C%29 , so
10%2F0.5=c%2Fsin%28123.26%5Eo%29-->20=c%2F0.8362(rounded)-->c=20%2A0.8362(rounded)-->highlight%28c=16.7%29 (rounded).

When you draw the 30%5Eo angle, you can locate
point A, at the vertex of the angle,
ray AB on one side of the angle,
and point C, at distance b=9 from A on the other side of the angle (side AC).
You know that point B is at distance a=10 from point C,
and that it is on ray AB,
so you just draw an arc with radius a=10 centered at point C.
The point where that arc intersects ray AB is point B.
angle