SOLUTION: 6 year ago the age of a mother six times the age of his son.after 8 year her age would be two and the half times the age of her son find their present age?

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Question 919092: 6 year ago the age of a mother six times the age of his son.after 8 year her age would be two and the half times the age of her son find their present age?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x son's age now. y mother's age now.
y-6 = 6(x-6)
-(y+8 = 2.5(x + 8))
-14 = 6(x-6) - 2.5(x+8)
-14 = 6x - 36 - 2.5x - 20
42 = 3.5x
42/3.5 = 12, son's age now.
His Mother is 42. y+=+6%28x-6%29+%2B+6 0r y+=+6%286%29+%2B+6+=+42
........
and ...checking...after 8 years
50 = 2.5(20)