SOLUTION: solve the equation for x in the interval [0,2pi)
13 sin x = 2 cos ^2 x -8
please help explain the steps
thanks in advance
Algebra ->
Trigonometry-basics
-> SOLUTION: solve the equation for x in the interval [0,2pi)
13 sin x = 2 cos ^2 x -8
please help explain the steps
thanks in advance
Log On
Question 919034: solve the equation for x in the interval [0,2pi)
13 sin x = 2 cos ^2 x -8
please help explain the steps
thanks in advance Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! solve the equation for x in the interval [0,2pi)
13 sin x = 2 cos ^2 x -8
--------------
I've done several similar problems today.
Make an effort.
email for help or to check your work.
