SOLUTION: solve the equation for solutions in the interval [0,2 pie): cos(x) = sin(2x)

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Question 918948: solve the equation for solutions in the interval [0,2 pie): cos(x) = sin(2x)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
the interval [0,2 pie):
cos(x) = sin(2x)
cos(x) = 2 sin(x)cos(x)
1/2 = sin(x), x = 30°, 150° 0r x = pi/6, 5pi/6
(cosx,sinx) unit circle Summary
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