Question 918873: The height, in meters, of a ball thrown upward upwards is given by h=50t - 5t^2, where t is in seconds. Determine how high the ball goes when it reaches its maximum height, and how long the ball is in the air.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! The height, in meters, of a ball thrown upward upwards is given by h=50t - 5t^2, where t is in seconds. Determine how high the ball goes when it reaches its maximum height, and how long the ball is in the air
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The max ht is the vertex of the parabola, at
t = -b/2a
t = -50/-10 = 5 seconds
h(5) = 50*5 - 5*5^2 = 125
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It takes 5 seconds to max ht, then 5 seconds to fall.
--> in the air 10 seconds
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