SOLUTION: The height of a projectile, propelled upward with an initial velocity of 40m/s, is given by the formula h= -4.9t^2 + 40t where t is the number of seconds after launch. How long aft
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Question 918871: The height of a projectile, propelled upward with an initial velocity of 40m/s, is given by the formula h= -4.9t^2 + 40t where t is the number of seconds after launch. How long after launch will the object be 10m above the ground? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The height of a projectile, propelled upward with an initial velocity of 40m/s, is given by the formula h= -4.9t^2 + 40t where t is the number of seconds after launch. How long after launch will the object be 10m above the ground?
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h= -4.9t^2 + 40t = 10
Solve for t.
