SOLUTION: How to go about graphing y = sec(x/2)? How to find do I find the vertical and horizontal asymptotes and intercepts of that function? Thank you

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Question 918700: How to go about graphing y = sec(x/2)?
How to find do I find the vertical and horizontal asymptotes and intercepts of that function?
Thank you
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How to go about graphing y = sec(x/2)?
How to find do I find the vertical and horizontal asymptotes and intercepts of that function?
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The easiest way to do this is::
1st:: Sketch a cosine curve.
2nd:: Label that curve so its period is 4pi
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3rd:: You have asymptotes at each point where cosine = 0
4th:: Where the cosine values are 1, sec(x/2) = 1
5th:: Since sec is inverse of cos, its curve increases
where cos decreases; its curve decreases where cos increases.
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graph%28400%2C400%2C-13%2C13%2C-4%2C4%2Ccos%28x%2F2%29%2C1%2Fcos%28x%2F2%29%29
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Cheers,
Stan H.
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