SOLUTION: Solve for x: log base a(x+6)- log base a(X+2)=log base a X. Assume that a>1.
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Question 918647
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Solve for x: log base a(x+6)- log base a(X+2)=log base a X. Assume that a>1.
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ewatrrr(24785)
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a^0 = 1
x+ 6 = x^2 + 2x
x^2 + x - 6 = 0
(x+3)(x-2) = 0 NOTE: x = -3 is an extraneous root log(-3) invalid
x = 2