SOLUTION: There are eight balls in an urn. They are identical except for color. Five are red, two are blue, and one is yellow. You are to draw a ball from the urn, note its color, and set it

Algebra ->  Probability-and-statistics -> SOLUTION: There are eight balls in an urn. They are identical except for color. Five are red, two are blue, and one is yellow. You are to draw a ball from the urn, note its color, and set it      Log On


   



Question 918229: There are eight balls in an urn. They are identical except for color. Five are red, two are blue, and one is yellow. You are to draw a ball from the urn, note its color, and set it aside. Then you are to draw another ball from the urn and note its color.
Let P(x, y) be the probability of choosing an x-colored ball on the first draw and a y-colored ball on the second draw. Compute the probability for each outcome of the experiment. (Enter your answers as fractions.)
P(R, R) =
P(R, B) =
P(R, Y) =
P(B, R) =
P(B, B) =
P(B, Y) =
P(Y, R) =
P(Y, B) =

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Look at the possible outcomes of drawing two balls.
RR
RB
RY
BR
BB
BY
YR
YB
YY - This is not possible since there is only one yellow ball.
Since each of the remaining outcomes is equally likely, they all have the same probability.
P=1%2F8