SOLUTION: GIVEN: Y=X^2-X-6 1. CALCULATE THE X-INTERCEPTS 2. CALCULATE THE Y-INTERCEPTS 3. CALCULATE THE TURNING POINT OF THIS GRAPH 4. SKETCH THE GRAPH, CLEARLY INDICATE ALL THE INTERCEP

Algebra ->  Coordinate-system -> SOLUTION: GIVEN: Y=X^2-X-6 1. CALCULATE THE X-INTERCEPTS 2. CALCULATE THE Y-INTERCEPTS 3. CALCULATE THE TURNING POINT OF THIS GRAPH 4. SKETCH THE GRAPH, CLEARLY INDICATE ALL THE INTERCEP      Log On


   

Question 918104: GIVEN: Y=X^2-X-6
1. CALCULATE THE X-INTERCEPTS
2. CALCULATE THE Y-INTERCEPTS
3. CALCULATE THE TURNING POINT OF THIS GRAPH
4. SKETCH THE GRAPH, CLEARLY INDICATE ALL THE INTERCEPTS AND TURNING POINTS
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The right member is factorable.

Doing in lower case instead,
y=%28x-3%29%28x%2B2%29

x-intercepts at -2 and 3.

y-intercept when x=0, meaning (0-3)(0+2)=-6,
this intercept is (0,-6).

Not sure what you mean for turning point. Maybe you mean the minimum value.
In middle of the intercepts, %28-2%2B3%29%2F2=1%2F2.
y=%281%2F2-3%29%281%2F2%2B2%29=%28-2%261%2F2%29%282%261%2F2%29=-6%261%2F4
VERTEX is (1/2, -6.25).

graph%28300%2C300%2C-5%2C5%2C-7%2C3%2Cx%5E2-x-6%29