SOLUTION: Simplify (-i)^19 (-1)^(-21/2)

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Question 917763: Simplify
(-i)^19
(-1)^(-21/2)

Found 2 solutions by Edwin McCravy, Theo:
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
All we need to know is that i2 = -1 and (-1)ħODD = -1
 
 
 
(-i)19 = (-1i)19 = (-1)19i19 = 
(-1)i19  = (-1)i18+1 = (-1)i18i1 =
(-1)i2*9i = (-1)(i2)9 = (-1)(-1)9 =
(-1)(-1)i = 1i = i
 
 
 
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Edwin


Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
powers of i are calculated as follows:

i^0 = 1
i^1 = i
i^2 = -1
i^3 = -i

this pattern repeats every 4 powers.

i^4 = i^0 = 1
i^5 = i^1 = i
i^6 = i^2 = -1
i^7 = i^3 = -i

i^8 = i^0 = 1
i^9 = i^1 = i
i^10 = i^2 = -1
i^11 = i^3 = -i

looking at the pattern, some smart person figured out that if you divide the exponent by 4, then you use the remainder to find the value of i.

for example:

to find the value of i^4, divide 4 by 4 to get a remainder of 0 and so the value of i^4 is the same as the value of i^0 which is equal to 1.

to find the value of i^5, divide 5 by 4 to get a remainder of 1 and so the value of i^5 is the same as the value of i^1 which is equal to i.

to find the value of i^10, divide 10 by 4 to get a remainder of 2 and so the value of i^10 is the same as the value of i^2 which is equal to -1.

etc.

use of this formula will help you solve the higher exponent problems.

your first problem is to find the value of i^19.

take 19 and divide it by 4 and you get a remainder of 3, so the value of i^19 = the value of i^3 which is equal to -i.

now to problem 2:

(-1)^(-21/2)

this can be solved as follows:

(-1)^(-21/2) is the same as:

((-1)^(1/2))^-21).

since (-1)^(1/2) is equal to sqrt(-1), this is the same as:

sqrt(-1)^-21.

since sqrt(-1) is equal to i, this is the same as:

i^-21.

since i^-21 is equal to 1/i^21, this is the same as:

1/i^21.

since i^21 is equal to i^1 which is equal to i, this is the same as:

1/i.

you can rationalize the denominator by multiplying the numerator and the denominator by i/i to get 1/i * i/i = i / i^2 which is equal to i / -1 which is equal to -i.

that should be your solution.

for problem 1, the solution is -i
for problem 2, the solution is also -i.

here's an online calculator where you can check your work.

http://www.mathsisfun.com/numbers/complex-number-calculator.html

here's a good tutorial on complex numbers.

http://www.purplemath.com/modules/complex.htm

here's the calculations i did in writing.

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