| 
 
 
| Question 917763:  Simplify
 (-i)^19
 (-1)^(-21/2)
 Found 2 solutions by  Edwin McCravy, Theo:
 Answer by Edwin McCravy(20064)
      (Show Source): 
You can put this solution on YOUR website! 
All we need to know is that i2 = -1 and (-1)ħODD = -1
 
 
 
(-i)19 = (-1i)19 = (-1)19i19 = 
(-1)i19  = (-1)i18+1 = (-1)i18i1 =
(-1)i2*9i = (-1)(i2)9 = (-1)(-1)9 =
(-1)(-1)i = 1i = i
 
 
 
--------------------------------------------------------
 
 
 
 Edwin 
Answer by Theo(13342)
      (Show Source): 
You can put this solution on YOUR website! powers of i are calculated as follows: 
 i^0 = 1
 i^1 = i
 i^2 = -1
 i^3 = -i
 
 this pattern repeats every 4 powers.
 
 i^4 = i^0 = 1
 i^5 = i^1 = i
 i^6 = i^2 = -1
 i^7 = i^3 = -i
 
 i^8 = i^0 = 1
 i^9 = i^1 = i
 i^10 = i^2 = -1
 i^11 = i^3 = -i
 
 looking at the pattern, some smart person figured out that if you divide the exponent by 4, then you use the remainder to find the value of i.
 
 for example:
 
 to find the value of i^4, divide 4 by 4 to get a remainder of 0 and so the value of i^4 is the same as the value of i^0 which is equal to 1.
 
 to find the value of i^5, divide 5 by 4 to get a remainder of 1 and so the value of i^5 is the same as the value of i^1 which is equal to i.
 
 to find the value of i^10, divide 10 by 4 to get a remainder of 2 and so the value of i^10 is the same as the value of i^2 which is equal to -1.
 
 etc.
 
 use of this formula will help you solve the higher exponent problems.
 
 your first problem is to find the value of i^19.
 
 take 19 and divide it by 4 and you get a remainder of 3, so the value of i^19 = the value of i^3 which is equal to -i.
 
 now to problem 2:
 
 (-1)^(-21/2)
 
 this can be solved as follows:
 
 (-1)^(-21/2) is the same as:
 
 ((-1)^(1/2))^-21).
 
 since (-1)^(1/2) is equal to sqrt(-1), this is the same as:
 
 sqrt(-1)^-21.
 
 since sqrt(-1) is equal to i, this is the same as:
 
 i^-21.
 
 since i^-21 is equal to 1/i^21, this is the same as:
 
 1/i^21.
 
 since i^21 is equal to i^1 which is equal to i, this is the same as:
 
 1/i.
 
 you can rationalize the denominator by multiplying the numerator and the denominator by i/i to get 1/i * i/i = i / i^2 which is equal to i / -1 which is equal to -i.
 
 that should be your solution.
 
 for problem 1, the solution is -i
 for problem 2, the solution is also -i.
 
 here's an online calculator where you can check your work.
 
 http://www.mathsisfun.com/numbers/complex-number-calculator.html
 
 here's a good tutorial on complex numbers.
 
 http://www.purplemath.com/modules/complex.htm
 
 here's the calculations i did in writing.
 
 
   
 
 
 
 
 
 
 
 
 
 
 | 
  
 | 
 |