SOLUTION: Sir, I have (a)1300 gms of 96.85% of Silver (b) 6500 gms of 65% of Silver.I want to make 73% by melting (b) with (a). How many gms from (b) I need to add with (a).Thank you.

Algebra ->  Finance -> SOLUTION: Sir, I have (a)1300 gms of 96.85% of Silver (b) 6500 gms of 65% of Silver.I want to make 73% by melting (b) with (a). How many gms from (b) I need to add with (a).Thank you.      Log On


   

Question 917741: Sir, I have (a)1300 gms of 96.85% of Silver (b) 6500 gms of 65% of Silver.I want to make 73% by melting (b) with (a). How many gms from (b) I need to add with (a).Thank you.
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
How much of the silver alloy is wanted?

R, grams of silver alloy wanted....?
Try using ALL of the 65% and find how much of the 96.85% to add to it?
%286500%2A65%2Bh%2A96.85%29%2F%286500%2Bh%29=73; if h is a reasonable value, then you have enough of the higher content silver material.

6500%2A65%2B96.85h=73%28h%2B6500%29
6500%2A65%2B96.85h=73h%2B6500%2A73
96.85h-73h=6500%2A73-6500%2A65
23.85h=8%2A6500
h=8%2A6500%2F23.85
h=2180----Too high for the amount available.

Try the other way or, how much mixture is wanted?


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NEW INFORMATION

The question was really this instead:
How much, u, of the 65% silver metal to mix with 1300 grams of the 96.85% silver metal
to make 73% silver?

highlight_green%28%2865u%2B%2896.85%29%281300%29%29%2F%28u%2B1300%29=73%29

Solve for u.