SOLUTION: (1+〖tan〗^2 θ)/(1+〖Cot〗^2 θ)=((1-tan A)/(1-Cot A))^2
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-> SOLUTION: (1+〖tan〗^2 θ)/(1+〖Cot〗^2 θ)=((1-tan A)/(1-Cot A))^2
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Question 917669
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(1+〖tan〗^2 θ)/(1+〖Cot〗^2 θ)=((1-tan A)/(1-Cot A))^2
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nihar*2013(34)
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