SOLUTION: Graph the following conic section x^2+8x+y^2-4y=16

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Question 917612: Graph the following conic section
x^2+8x+y^2-4y=16
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Graph the following conic section
x^2+8x+y^2-4y=16
complete the square
(x^2+8x+16)+(y^2-4y+4)=16+16+4
(x+4)^2+(y-2)^2=36
This is an equation of a circle with center at (-4,2) with radius=6
see graph of circle below:
(36-(x+4)^2)^.5+2