SOLUTION: how many ounces of a 4% acid solution and how many ounces of a 10% acid solution must be mixed to make 24 ounces of a 6% acid solution?

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Question 917483: how many ounces of a 4% acid solution and how many ounces of a 10% acid solution must be mixed to make 24 ounces of a 6% acid solution?
Found 2 solutions by richwmiller, Alan3354:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
We need a total of 24 oz. at 6%
We want to know how many oz. at 4% to mix with 10%
a+b=24,
0.04*a+0.1*b=0.06*24
a=24-b
0.04*(24-b)+0.1*b=1.44
0.96-0.04b+0.1*b=1.44
0.06*b=0.48
b=8
a=24-b
a=16 oz. at 4%
b=8 oz. at 10%
check
0.04*16+0.1*8=0.06*24
0.64+0.8=1.44
1.44=1.44
ok
codemx1

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Do it like this one. Only the numbers are different.
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Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use?
================
e = amount of 8%
f = amount of 56%
---
e+ f = 8 (total solution)
8e + 56f = 20*8 (total saline)
---
e+ f = 8
e + 7f = 20
------------ Subtract
-6f = -12
f = 2
e = 6