SOLUTION: I am having some problems solving these problems Use the quadratic formula to solve each of the quadratic equations 2x^2-5x=3 and also 3x^2-2x+1=0 Thank you

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I am having some problems solving these problems Use the quadratic formula to solve each of the quadratic equations 2x^2-5x=3 and also 3x^2-2x+1=0 Thank you      Log On


   

Question 91744: I am having some problems solving these problems
Use the quadratic formula to solve each of the quadratic equations
2x^2-5x=3
and also 3x^2-2x+1=0
Thank you
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x using the quadratic formula: x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a
Problem 1.
2x%5E2-5x+=+3 Subtract 3 from both sides to get your equation into standard form: ax%5E2%2Bbx%2Bc+=+0
2x%5E2-5x-3+=+0 Apply the formula:
x+=+%28-%28-5%29%2B-sqrt%28%28-5%29%5E2-4%282%29%28-3%29%29%29%2F2%282%29 Now evaluate this.
x+=+%285%2B-sqrt%2825%2B24%29%29%2F4
x+=+%285%2B-sqrt%2849%29%29%2F4
x+=+%285%2F4%29%2B7%2F4
x+=+12%2F4
x+=+3 or
x+=+%285%2F4%29-7%2F4
x+=+-2%2F4
x+=+-1%2F2
You can use the above as a guide to solve problem 2.