SOLUTION: Find the reference number for each value of t. t = 11π/5 t = − 10π/7 t = 6 t = −7 Please explain how these would be solved. Thank you

Algebra ->  Trigonometry-basics -> SOLUTION: Find the reference number for each value of t. t = 11π/5 t = − 10π/7 t = 6 t = −7 Please explain how these would be solved. Thank you       Log On


   

Question 917431: Find the reference number for each value of t.
t = 11π/5

t = − 10π/7
t = 6
t = −7

Please explain how these would be solved.
Thank you
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the reference number for each value of t.
***
t = 11π/5
rotate cc (2π(1 rev)+ π/5) radians
reference angle: π/5 radians(In quadrant I)
..
t = − 10π/7
rotate cw (π + 3π/7) radians
reference angle: 3π/7 radians (In quadrant II)
..
t = 6
rotate cc 6 radians
reference angle=2π-6=0.2832 radians (in quadrant IV)
..
t = −7
rotate cw 7 radians
reference angle=7-2π=0.7168 radians (in quadrant IV)
..
note: radians are real numbers