SOLUTION: A binomial settings: "6 boxes of pottery are checked for damaged items. The probability that a box of pottery contains a damaged item is p = 0.2 We can assume independence.
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Question 917401: A binomial settings: "6 boxes of pottery are checked for damaged items. The probability that a box of pottery contains a damaged item is p = 0.2 We can assume independence.
Calculate P(X=3) by hand. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A binomial settings: "6 boxes of pottery are checked for damaged items. The probability that a box of pottery contains a damaged item is p = 0.2 We can assume independence.
Calculate P(X=3) by hand.
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P(x = 3) = 6C3(0.2)^3*(0.8)^3 = [(6*5*4)/(1*2*3)](0.16)^3 = 20*0.004
= 0.08
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Cheers,
Stan H.
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