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| Question 917391:  8 men and 16 women can do a work in 8 days.40 men and 48 women can do the same work in 2 days.how many days are required for 6 men and 12 women to do the same work.
 Found 2 solutions by  josgarithmetic, MathTherapy:
 Answer by josgarithmetic(39630)
      (Show Source): 
You can put this solution on YOUR website! Let m = how many days 1 man could do the work if alone; let w = how many ways 1 woman could do the same work alone.
 
 
  and   
 Two equations, two unknown variables; simplify each equation and solve the system.
 
 The first arrangement of workers
 
  to account for 1 job 
  , and LCD is mw 
   
 Second arrangement of workers
 
  
  
   
 Two equal formulas for mw.
 
  
  
  This is the relationship between m and w, which through substitution,
 allows to find through either of the mw equations, to solve for w and m,
 the NUMBER OF DAYS for one woman to do one job and the NUMBER OF DAYS for one man to do one job.
 
 Use this system:
 
   
 (Further steps, not yet done, but you need to do them.)
 
 You can then answer the actual question from there, using RT=J for
 rate time job, uniform work rates formula.
 
 Substituting
  in the  , solving for m gives 
  days and this means  days. 
 Now, use those to solve the question asked.
 
 
 Rate in jobs per day for the 6 men and 12 women,
 
   
 Let t be the number of days for this group to do 1 job.
 The uniform rates rule gives:
 
  Solve for t.
 -
 -
 RESULT:
  days.Answer by MathTherapy(10556)
      (Show Source): 
You can put this solution on YOUR website! 8 men and 16 women can do a work in 8 days.40 men and 48 women can do the same work in 2 days.how many days are required for 6 men and 12 women to do the same work.
 
 Time 6 men and 12 women take:
  days You can do the check!!
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