SOLUTION: Two squares have perimeters of 20 inches and 48 inches. How much longer is a side of the larger square than a side of the smaller square? A. 6 inches B. 7 inche

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Question 917347: Two squares have perimeters of 20 inches and 48 inches. How much longer is a side of the larger square than a side of the smaller square?


A.
6 inches


B.
7 inches


C.
8 inches


D.
12 inches
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
it's a square, so P=4a

4a=20
4a1=48
a=20%2F4
a=5
4a1=48
a1=12
a1-a=12-5=7
answer:
B.
7+inches