SOLUTION: Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one ticket and one same-day ticket is $50. For one performance, 30 advance tickets

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Question 917265: Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one ticket and one same-day ticket is $50. For one performance, 30 advance tickets and 25 same-day tickets were sold. The total amount paid for the tickets was $1,325. What is the price of each kind of ticket.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!

x, price of advanced ticket
y, price of same-day ticket

That combined cost: x%2By=50

The one performance: 30x%2B25y=1325

Two linear equation in two unknown variables. Simplify the revenue equation first, and then solve the resulting system any way you wish. Elimination method will likely be most comfortable, at least part-way through. Divide members of the one performance equation by 5 to simplify. If you then multiply both members of the "combined cost" equation by 5, you will be able to subtract one equation from the other to eliminate y, and continue to get a value for x.