SOLUTION: I really need your help in solving this problem. I appreciate your time and efforts. Have a terrific day :) Here is the question? Raising Turkeys. The Formula T = 2000m/(m+1) gi

Algebra ->  Rational-functions -> SOLUTION: I really need your help in solving this problem. I appreciate your time and efforts. Have a terrific day :) Here is the question? Raising Turkeys. The Formula T = 2000m/(m+1) gi      Log On


   



Question 917144: I really need your help in solving this problem. I appreciate your time and efforts. Have a terrific day :) Here is the question?
Raising Turkeys. The Formula T = 2000m/(m+1) give the number T of Turkeys on a poultry farm m months after the beginning of the year. How many Turkeys will there be on the farm by the end of July?

Found 2 solutions by MathLover1, Edwin McCravy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

T+=+2000m%2F%28m%2B1%29 ....if month is July+, 7th month, we have
T+=+%282000%2A7%29%2F%287%2B1%29+
T+=+14000%2F8
T+=+1750

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Other tutors just give you the answer.  I like to analyze them.
If you'll analyze your problems your understanding increases.

All of January is 1 month,
plus all of February is 2 months,
plus all of March is 3 months,
plus all of April is 4 months,
plus all of May is 5 months,
plus all of June is 6 months,
plus all of July is 7 months,

So that's 7 months.  So we substitute 7 for m
in the equation

T+=+%282000m%29%2F%28m%2B1%29

T+=+%282000%287%29%29%2F%28%287%29%2B1%29

T+=+14000%2F%287%2B1%29

T+=+14000%2F8

T+=+1750  1750 turkeys on the farm.

---------------------

You weren't asked this but it would help you understand what's
happening on the turkey farm by substuting the numbers from
1 month through 12 months in the formula, like we did with 7
months above:

At the end of January,   when m=1, there will be 1000 turkeys.
At the end of February,  when m=2, there will be 1333 turkeys.
At the end of March,     when m=3, there will be 1500 turkeys.
At the end of April,     when m=4, there will be 1600 turkeys.
At the end of May,       when m=5, there will be 1667 turkeys.
At the end of June,      when m=6, there will be 1714 turkeys.
At the end of July,      when m=7, there will be 1750 turkeys. <--we did that!
At the end of August,    when m=8, there will be 1778 turkeys.
At the end of September, when m=9, there will be 1800 turkeys.
At the end of October,  when m=10, there will be 1818 turkeys.
At the end of November, when m=11, there will be 1833 turkeys.
At the end of December, when m=12, there will be 1846 turkeys. 

Notice that the rate of increase slows up and the farm will never
have millions of turkeys.  In fact there will never be quite
2000 turkeys.  It's interesting to think about what standard
factors would cause that to be the case.

Edwin