SOLUTION: Six items are taken at random from a box of 17 items and inspected. The box is rejected if more than 4 items are found to be faulty. If there are 6 faulty items in the box, find t
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-> SOLUTION: Six items are taken at random from a box of 17 items and inspected. The box is rejected if more than 4 items are found to be faulty. If there are 6 faulty items in the box, find t
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Question 916981: Six items are taken at random from a box of 17 items and inspected. The box is rejected if more than 4 items are found to be faulty. If there are 6 faulty items in the box, find the probability that the box is rejected. Answer by Theo(13342) (Show Source):
x is the number of defectives items.
n is the total number of items.
p is the probability of getting one that is defective.
q is the probability of getting one that is not defective
the probability of getting one that is not defective is equal to 1 minus the probability of getting one that is defective.
in this problem:
n = 17
x = 0 to 6
p = 6/17 = .352941...
q = 11/17 = .647058...
c(n,x) is the combination of n things taken x at a time where order doesn't matter.
this formula is:
c(n,x) = n! / (x! * (n-x)!)
you want to find the probability that more than 4 are defective out of 6 selected.
this means the probability that 5 or 6 are defective.
4 defective passes the test and the box is no rejected.
5 or 6 defective fails the test and the box is rejected.
add these together and you get p(5 or 6) = .023195 rounded to 6 decimal places.
that's your solution.
the probability that the box will be rejected = .023195 *****
the following excel spreadsheet shows all the probabilities.
you can see that the total probability is equal to 1.
you can slso see that the probability of 5 or 6 defectives when you pick 6 out of the box of 17 is equal to .023195.
the column marked x contains the number of defectivdes.
the column markes p(x) contains the probability of getting that many defectives.