Question 916905: Kylie was on a long 330 mile road trip. The first part of the trip there was lots of traffic, she only averaged 25 mph. The second part of the trip there was no traffic so she could drive 56 mph. If the trip took her 7 hours, how long did she travel at each speed?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39621)   (Show Source):
You can put this solution on YOUR website! _______________rate________time_________distance
SLOW___________25___________x____________25x
FAST___________56___________y____________56y
Totals______________________7____________330
Answer by MathTherapy(10555)  (Show Source):
You can put this solution on YOUR website!
Kylie was on a long 330 mile road trip. The first part of the trip there was lots of traffic, she only averaged 25 mph. The second part of the trip there was no traffic so she could drive 56 mph. If the trip took her 7 hours, how long did she travel at each speed?
Let time taken to travel 1st leg, be T
Then time taken to travel 2nd leg = 7 - T
Distance on 1st leg, plus distance om 2nd leg, equals total distance, OR
25T + 56(7 - T) = 330
25T + 392 - 56T = 330
25T - 56T = 330 - 392
- 31T = - 62
T, or time taken to travel 1st leg =  or  hours
Time taken to travel 2nd leg: 7 - 2, or  hours
You can do the check!!
===================
Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously.
For FREE info and answers to questions about the ASVAB exam, the NYS 3 – 8 city/state wide exams,GENERAL
MATH and HOMEWORK QUESTIONS, or MATH QUESTIONS related to the Regents Integrated Algebra,
Regents Geometry, Regents Algebra 2/Trigonometry, SHSAT, COOP/HSPT/TACHS, PSAT, SAT, ACT, SSAT/ISEE,
GRE, CLEP, and the TASC/GED, you can visit: http://asvabstudyzone.freeforums.net/.
|
|
|
