SOLUTION: leg A 15 Leg B x Hypotenuse 4x

Algebra ->  Pythagorean-theorem -> SOLUTION: leg A 15 Leg B x Hypotenuse 4x      Log On


   

Question 916715: leg A 15
Leg B x
Hypotenuse 4x
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
a^2 + b^2 = c^2

15^2 + x^2 = (4x)^2

225 + x^2 = 16x^2

225 = 16x^2 - x^2

225 = 15x^2

15x^2 = 225

x^2 = 225/15

x^2 = 15

x = sqrt(15)


Leg A: 15

Leg B: sqrt(15)

Hypotenuse: 4*sqrt(15)


Let me know if you need more help or if you need me to explain a step in more detail.
Feel free to email me at jim_thompson5910@hotmail.com
or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html

Thanks,

Jim