SOLUTION: Larry invested part of his 17,000 advance at 6% annual simple interest and the rest at 9% if his total yearly interest from both accounts was $1320 find the amount invested at each

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Question 916691: Larry invested part of his 17,000 advance at 6% annual simple interest and the rest at 9% if his total yearly interest from both accounts was $1320 find the amount invested at each rate
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x amount at 9%
.09x + .06(17000-x) = $1320
x = (1320- 1020)/.03 = $10,000 at 9%,
17000-10000 $7000 at 6%