Question 916549: Find the points on the graph of the function that are closest to the given point.
f(x) = (x + 2)^2, (7, 8)
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the points on the graph of the function that are closest to the given point.
f(x) = (x + 2)^2, (7, 8)
---------
Points on the graph have the form (x,(x+2)^2)
------
distance = sqrt[(7-x)^2+(8-(x+2)^2)^2
------
d = sqrt[(49-14x+x^2 + (64-16(x+2)^2+(x+2)^4)]
------
Simplify the radicand.
Take the derivative.
Set it to zero and solve for "x" and then the corresponding f(x).
-----------
Cheers,
Stan H.
=============
|
|
|