You can
put this solution on YOUR website!
Hi
Re TY, might recommend doing it the old fashion way
3x-4 √(3x^3 - 7x^2 + 7x -4)
You will find: (x^2 - x + 1)/(3x-4) = (x^2 - x + 1)
using Synthetic Division Technique and using 4/3 for the Divisor much like one would do if it were a root
2x-3 = 0, x = 4/3
that is as if (3x-4)3(x^3 - 7/3x^2 + 7/3x - 4/3) = 0
0r (3x-4)( x^3 - 7/3x^2 + 7/3x - 4/3) = 0
4/3 1 -7/3 7/3 -4/3
4/3 -4/3 4/3
1 -1 1 0
(x^2 - x + 1)/(3x-4) = (x^2 - x + 1)