SOLUTION: I am confused on how to solve this, the directions say "Sketch the graph of each line." Each problem had an equation like y=-4x/5 or y=3/2x-1 with a graph below it. What do I do?

Algebra ->  Coordinate-system -> SOLUTION: I am confused on how to solve this, the directions say "Sketch the graph of each line." Each problem had an equation like y=-4x/5 or y=3/2x-1 with a graph below it. What do I do?       Log On


   



Question 916079: I am confused on how to solve this, the directions say "Sketch the graph of each line." Each problem had an equation like y=-4x/5 or y=3/2x-1 with a graph below it. What do I do?
I looked in my notes and I think I have to do sort of inverse operations and substitute numbers for y=mx=b but I'm not sure.
Could you just work through one of the above example problems and help? Also what do I do about fractions?
Thank you!!

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll show you how to graph something like y+=+%283%2F2%29x-1

Looking at y=%283%2F2%29x-1 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=3%2F2 and the y-intercept is b=-1


Since b=-1 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 3%2F2, this means:

rise%2Frun=3%2F2


which shows us that the rise is 3 and the run is 2. This means that to go from point to point, we can go up 3 and over 2



So starting at , go up 3 units


and to the right 2 units to get to the next point



Now draw a line through these points to graph y=%283%2F2%29x-1

So this is the graph of y=%283%2F2%29x-1 through the points and

Let me know if you need more help or if you need me to explain a step in more detail.
Feel free to email me at jim_thompson5910@hotmail.com
or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html

Thanks,

Jim