SOLUTION: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together t

Algebra ->  Rate-of-work-word-problems -> SOLUTION: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together t      Log On


   



Question 91598: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks
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Let "the job" be mix 20 drinks
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Steven DATA:
Time = 5 min/job ; Rate = 1/5 job/min
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Sue DATA:
Time = 10 min/job ; Rate = 1/10 job/min
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Jack DATA:
Time = 15 min/job ; Rate = 1/15 job/min
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Together DATA:
Time = x min/job ; Rate = 1/x job/min
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EQUATION:
rate + rate + rate = together rate
1/5 + 1/10 + 1/15 = 1/x
Multiply thru by 30x to get:
6x + 3x + 2x = 30
11x = 30
x = (30/11) min/job
Time for all working together to mix 20 drinks = 30/11 = 2.73 minutes
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Cheers,
Stan H.