SOLUTION: How would you graph the lines y-3=-2x and -2x+5y=-10 without changing the form?

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Question 915231: How would you graph the lines y-3=-2x and -2x+5y=-10 without changing the form?
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
y-3=-2x, simply a minor change from slope-intercept form, with slope -2 and y-intercept (0,3). Graphable easily using the data.

-2x%2B5y=-10, depends on how well you can understand standard form. Slope is 2%2F5, but you want at least one of the axis intercepts. Find either intercept you want. You CAN change the form to solve for one of them, unless you know something more efficient. Handling mentally, if x=0, then you can divide -10 by 5, and this means y=-2; so the y-intercept is (0,-2). Use slope 2%2F5 and y-intercept (0,-2) to plot the graph.


Done; no change in form used, except for a mental operation.
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C-2x%2B3%2C%282%2F5%29x-2%29