SOLUTION: Can someone please help me solve this problem. I am having trouble understanding how to solve it. 3x+4y=12 with this solutions: (0, ),(2/3, ),( ,0),and (-2/3, ). Thank you.

Algebra ->  Equations -> SOLUTION: Can someone please help me solve this problem. I am having trouble understanding how to solve it. 3x+4y=12 with this solutions: (0, ),(2/3, ),( ,0),and (-2/3, ). Thank you.      Log On


   

Question 91500: Can someone please help me solve this problem. I am having trouble understanding how to solve it.
3x+4y=12 with this solutions: (0, ),(2/3, ),( ,0),and (-2/3, ).
Thank you.
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
3X+4Y=12 NOW SUBSTITUTE 0 FOR X & SOLVE FOR Y:
3*0+4Y=12
4Y=12
Y=12/4
Y=3 ANSWER IS (0,3)
3*2/3+4Y=12
6/3+4Y=12
2+4Y=12
4Y=12-2
4Y=10
Y=10/4
Y=5/2 ANSWER (2/3,5/2)
3X+4*0=12
3X=12
X=12/3
X=4 ANSWER (4,0)
3*-2/3+4Y=12
-6/3+4Y=12
-2+4Y=12
4Y=12+2
4Y=14
Y=14/4
Y=7/2 ANSWER (-2/3,7/2)
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-3x%2F4+%2B3%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -3x/4 +3).