SOLUTION: true or false the last line of synthetic division for (2x^4 - 5x^3 + 7x^2 - 3x +1)/(x - 3) gives coefficients for the quotient of 2,1,8, and 21?

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Question 914979: true or false
the last line of synthetic division for (2x^4 - 5x^3 + 7x^2 - 3x +1)/(x - 3) gives coefficients for the quotient of 2,1,8, and 21?

Found 2 solutions by ewatrrr, Edwin McCravy:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi
my colleague is totally correct. TY for the catch

3 2 -5 7 -3 1
6 3 30 81
2 1 10 27 82
2x^3 + x^2 +10x + 27 + 82/(x-3)

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
The other tutor made a mistake.

We'll see what it should be.  But first of all you should not write 

2x^4 - 5x^3 + 7x^2 - 3x +1/ x - 3

because you must indicate with parentheses where every numerator 
and denominator begins and ends.  You use a "{" to show where they
begin and a ")" to show where they end.  IOW, you should have

(2x^4 - 5x^3 + 7x^2 - 3x +1)/(x - 3)

Without the parentheses the only things divided are the 1 and the x.
So in the future be sure to use parentheses to show where numerators
and denominators begin and end.


3 | 2 -5  7 -3  1
  |    6  3 30 81
    2  1 10 27 82

No, it's 2,1,10,27, and 82.  The answer to the division is 2x%5E3%2B1x%5E2%2B10x%2B27%2B82%2F%28x-3%29

Edwin