SOLUTION: a zero of the function f(x) = 4x^4 - 8x^3 - 19x^2 + 23x

Click here to see ALL problems on Numbers Word Problems

Question 914978: a zero of the function f(x) = 4x^4 - 8x^3 - 19x^2 + 23x - 6 is?
Found 2 solutions by richwmiller, ewatrrr:
Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website!
4x^4 - 8x^3 - 19x^2 + 23x - 6
x+2 is a factor
-2 is a zero
which leaves
4x^3-16x^2+ 13x-3
x-3 is a factor
3 is a zero
which leaves
4x^2-4x+1
x-0.5 is a factor
0.5 is a zero
which leaves
4x-2
x-0.5 is a factor again
0.5 is a zero again

Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!

Hi
a zero of the function f(x) = 4x^4 - 8x^3 - 19x^2 + 23x - 6 is: x = -2
(x+2) a factor
Using Synthetic Division

-2 4 -8 -19 23 -6
-8 32 -26 6
4 -16 13 -3 0
4x^3 - 16x^2 - 13x - 3 (3 a zero of this)

3 4 -16 13 -3
12 -12 3
4 -4 1 0 0
(x+2)(x-3)(4x^2 - 4x + 1) = (x+2)(x-3)(2x-1)^2
roots: -2, 3, 1/2(multiplicity of two)

SOLUTION: a zero of the function f(x) = 4x^4 - 8x^3 - 19x^2 + 23x - 6 is?