SOLUTION: Please check my work for expanding logs: Here is the problem: http://i.imgur.com/zPBO0cw.png My work: log(x^2-4)-log(x^3)-log(x+1) =2log(x-4)-3log(x)-log(x+1) Is th

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Please check my work for expanding logs: Here is the problem: http://i.imgur.com/zPBO0cw.png My work: log(x^2-4)-log(x^3)-log(x+1) =2log(x-4)-3log(x)-log(x+1) Is th      Log On


   

Question 914714: Please check my work for expanding logs:
Here is the problem:
http://i.imgur.com/zPBO0cw.png
My work:
log(x^2-4)-log(x^3)-log(x+1)
=2log(x-4)-3log(x)-log(x+1)
Is that correct?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
your work:
log%28x%5E2-4%29-log%28x%5E3%29-log%28x%2B1%29 this is correct
= 2log%28%28x-4%29%29+-3log%28%28x%29%29-log%28%28x%2B1%29%29 ...this part 2log%28%28x-4%29%29 is incorrect; you have %28x%5E2-4%29=x%5E2-2%5E2=%28x-2%29%28x%2B2%29, only if you have log%28%28x-4%29%5E2%29 you can write it as 2log%28%28x-4%29%29
so,
log%28%28x%5E2-4%29%29%2B3log%28%28x%29%29-log%28%28x%2B1%29%29