SOLUTION: Here's my problem. Please help me. Thank youuu. A machineis supposed to mix peanuts, hazelnuts, cashews, and pecans in the ratio 5:2:2:1. A can containing 500 of these mixed nut

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Here's my problem. Please help me. Thank youuu. A machineis supposed to mix peanuts, hazelnuts, cashews, and pecans in the ratio 5:2:2:1. A can containing 500 of these mixed nut      Log On


   



Question 914499: Here's my problem. Please help me. Thank youuu.
A machineis supposed to mix peanuts, hazelnuts, cashews, and pecans in the ratio 5:2:2:1. A can containing 500 of these mixed nuts was found to have 269 peanuts 74 cashews and 45 pecans. How many hazelnuts are there?

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
269 peanuts, 74 cashews, and 45 pecans add up to 269%2B74%2B45=388 nuts.
Since there are 500 nuts in the can,
and each nut is expected to be
either a peanut, or a hazelnut, or a cashew, or a pecan
(no almonds, chestnuts, filberts or any other nuts),
then the remaining 500-388=highlight%28112%29 nuts are hazelnuts.
If you want to write both calculations in one, use parentheses, like this:
500-%28269%2B74%2B45%29=highlight%28112%29 ,
or (showing your work)
500-%28269%2B74%2B45%29=500-388=highlight%28112%29 .

Obviously, that machine is not doing a good job, or else it is mixing the bulk product correctly, but the mix segregates (de-mixes a bit) as it is being packaged.
If the nuts were in the ratio 5:2:2:1,
we could split that can containing 500 nuts into 50 groups of 10 nuts,
with each group including
5 peanuts, 2 hazelnuts, 2 cashews, and 1 pecan.