SOLUTION: I need to solve system of equations by addition method 2x+y=6 4x+2y=12 I am lost. Thank you.

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Question 914391: I need to solve system of equations by addition method
2x+y=6
4x+2y=12
I am lost. Thank you.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

2%2Ax%2B1%2Ay=6
4%2Ax%2B2%2Ay=12

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 2 and 4 to some equal number, we could try to get them to the LCM.

Since the LCM of 2 and 4 is 4, we need to multiply both sides of the top equation by 2 and multiply both sides of the bottom equation by -1 like this:

2%2A%282%2Ax%2B1%2Ay%29=%286%29%2A2 Multiply the top equation (both sides) by 2
-1%2A%284%2Ax%2B2%2Ay%29=%2812%29%2A-1 Multiply the bottom equation (both sides) by -1


So after multiplying we get this:
4%2Ax%2B2%2Ay=12
-4%2Ax-2%2Ay=-12

Notice how 4 and -4 add to zero, 2 and -2 add to zero, 12 and -12 and to zero (ie 4%2B-4=0) 2%2B-2=0, and 12%2B-12=0)


So we're left with

0=0


which means any x or y value will satisfy the system of equations. So there are an infinite number of solutions


So this system is dependent