SOLUTION: In the equation dx-2y=-8 for what value of d is the graph of the equation parallel to 2y-5x+1=0? the y axis? the x axis?

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Question 914268: In the equation dx-2y=-8 for what value of d is the graph of the equation parallel to 2y-5x+1=0? the y axis? the x axis?
Found 2 solutions by mananth, MathLover1:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
dx-2y=-8 for what value of d is the graph of the equation parallel to 2y-5x+1=0? the y axis? the x axis?
slopes are equal since the lines are parallel
dx-2y=-8
2y=dx+8
y=d/2 x +4
2y-5x+1=0?
2y=5x-1
y=5/2x -1/2
d/2 = 5/2
d= 5
If dx-2y=-8 is parallel to X axis
d=0
If dx-2y=-8 is parallel to Y axis
d can take innumerable values

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

parallel lines have same+slope; so, write both equations in slope-intercept form
dx-2y=-8 ..........eq.1
dx%2B8=2y
y=%28d%2F2%29x%2B8%2F2 => slope is %28d%2F2%29

2y-5x%2B1=0 ........eq.2
2y=5x-1
y=%285%2F2%29x-1%2F2+=> slope is %285%2F2%29
so,
%28d%2F2%29=+5%2F2 => d=5

than you have 5x-2y=-8 or y=%285%2F2%29x%2B8%2F2+