SOLUTION: The graph of a logarithmic function f with the vertical asymptote x = −9 and x-intercept (−8, 0) . It goes through the point (0, 2) The function is: f(x) =

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: The graph of a logarithmic function f with the vertical asymptote x = −9 and x-intercept (−8, 0) . It goes through the point (0, 2) The function is: f(x) =       Log On


   

Question 914202: The graph of a logarithmic function f with the vertical asymptote x = −9
and x-intercept (−8, 0) . It goes through the point (0, 2)
The function is:
f(x) =
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
This is most of the way to an answer.

Instead of something as f%28x%29=a%2Alog%28%28x%29%29, you have something like f%28x%29=a%2Alog%28%28x%2B9%29%29%2Bk. That is based on the given asymptote.

This is what happens with the x-intercept:
a%2Alog%28%28-8%2B9%29%29%2Bk=0
a%2Alog%28%281%29%29%2Bk=0
a%2A0%2Bk=0
highlight_green%28k=0%29

This happens using the y-intercept:
a%2Alog%28%289%29%29%2Bk=2
and you just found k=0, so
a%2Alog%28%289%29%29=2
highlight_green%28a=2%2Flog%28%289%29%29%29

You could pick the base you want or need for the logarithm, but at least you know you have highlight%28f%28x%29=%282%2Flog%28%289%29%29%29log%28%28x-9%29%29%29.