SOLUTION: For design purposes, the large gear is the circle x^2+y^2=16. The smaller gear is a circle centered at (7,0) and tangent to the larger circle. Find the equation of the smaller gear

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: For design purposes, the large gear is the circle x^2+y^2=16. The smaller gear is a circle centered at (7,0) and tangent to the larger circle. Find the equation of the smaller gear      Log On


   

Question 914155: For design purposes, the large gear is the circle x^2+y^2=16. The smaller gear is a circle centered at (7,0) and tangent to the larger circle. Find the equation of the smaller gear.
Link to see the what the gear looks like: http://imgur.com/a/lWU6m
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The smaller gear center is (7,0)
The larger gear radius is R%5BL%5D=4.
The smaller gear radius is R%5BS%5D=7-4=3
The smaller gear equation is then
%28x-7%29%5E2%2By%5E2=3%5E2
%28x-7%29%5E2%2By%5E2=9